javascript tutorial - [Solved-5 Solutions] Radio button is selected via jQuery - javascript - java script - javascript array

To get the value of the selected radioName item of a form with id myForm:

$('input[name=radioName]:checked', '#myForm').val()

Here's an example:

$('#myForm input').on('change', function() {
   alert($('input[name=radioName]:checked', '#myForm').val()); 
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<input type="radio" name="radioName" value="1" /> 1 <br />
<input type="radio" name="radioName" value="2" /> 2 <br />
<input type="radio" name="radioName" value="3" /> 3 <br />
</form>

Use this..

$("#myform input[type='radio']:checked").val();

If we already have a reference to a radio button group, for example:

var myRadio = $('input[name=myRadio]');

Use the filter() function, not find(). (find() is for locating child/descendant elements, whereas filter() searches top-level elements in your selection.)

var checkedValue = myRadio.filter(':checked').val();

Note: This answer was originally correcting another answer that recommended using find(), which seems to have since been changed. find() could still be useful in the situation where we already had a reference to a container element, but not to the radio buttons, e.g.:

var form = $('#mainForm');
...
var checkedValue = form.find('input[name=myRadio]:checked').val();

This should work:

$("input[name='radioName']:checked").val()

We can use the :checked selector along with the radio selector.

 $("form:radio:checked").val();