In the previous post, we introduced Queue and discussed array implementation. In this post, linked list implementation is discussed. The following two main operations must be implemented efficiently.

In a Queue data structure, we maintain two pointers, front and rear. The front points the first item of queue and rear points to last item.

enQueue() This operation adds a new node after rear and moves rear to the next node.

deQueue() This operation removes the front node and moves front to the next node.

Java programming

// Java program for linked-list implementation of queue
  
// A linked list (LL) node to store a queue entry
class QNode
{
    int key;
    QNode next;
     
    // constructor to create a new linked list node
    public QNode(int key) {
        this.key = key;
        this.next = null;
    }
}
 
// A class to represent a queue
//The queue, front stores the front node of LL and rear stores ths
//last node of LL
class Queue
{
    QNode front, rear;
      
    public Queue() {
        this.front = this.rear = null;
    }
      
    // Method to add an key to the queue.  
    void enqueue(int key)
    {
         
        // Create a new LL node
        QNode temp = new QNode(key);
      
        // If queue is empty, then new node is front and rear both
        if (this.rear == null)
        {
           this.front = this.rear = temp;
           return;
        }
      
        // Add the new node at the end of queue and change rear
        this.rear.next = temp;
        this.rear = temp;
    }
      
    // Method to remove an key from queue.  
    QNode dequeue()
    {
        // If queue is empty, return NULL.
        if (this.front == null)
           return null;
      
        // Store previous front and move front one node ahead
        QNode temp = this.front;
        this.front = this.front.next;
      
        // If front becomes NULL, then change rear also as NULL
        if (this.front == null)
           this.rear = null;
        return temp;
    }
}
  
   
// Driver class
public class Test
{
    public static void main(String[] args) 
    {
        Queue q=new Queue();
        q.enqueue(10);
        q.enqueue(20);
        q.dequeue();
        q.dequeue();
        q.enqueue(30);
        q.enqueue(40);
        q.enqueue(50);
         
        System.out.println("Dequeued item is "+ q.dequeue().key);
    }
}

 Output:

Dequeued item is 30

Time Complexity: Time complexity of both operations enqueue() and dequeue() is O(1) as we only change few pointers in both operations. There is no loop in any of the operations.

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