Given two linked lists, represented as linked lists (every character is a node in linked list). Write a function compare() that works similar to strcmp(), i.e., it returns 0 if both strings are same, 1 if first linked list is lexicographically greater, and -1 if second string is lexicographically greater.
Examples:
Input: list1 = g->e->e->k->s->a
list2 = g->e->e->k->s->b
Output: -1
Input: list1 = g->e->e->k->s->a
list2 = g->e->e->k->s
Output: 1
Input: list1 = g->e->e->k->s
list2 = g->e->e->k->s
Output: 0
Java programming
class LinkedList {
Node head;
static Node a, b;
static class Node {
char data;
Node next;
Node(char d) {
data = d;
next = null;
}
}
int compare(Node node1, Node node2) {
if (node1 == null && node2 == null) {
return 1;
}
while (node1 != null && node2 != null && node1.data == node2.data) {
node1 = node1.next;
node2 = node2.next;
}
if (node1 != null && node2 != null) {
return (node1.data > node2.data ? 1 : -1);
}
if (node1 != null && node2 == null) {
return 1;
}
if (node1 == null && node2 != null) {
return -1;
}
return 0;
}
public static void main(String[] args) {
LinkedList list = new LinkedList();
Node result = null;
list.a = new Node('g');
list.a.next = new Node('e');
list.a.next.next = new Node('e');
list.a.next.next.next = new Node('k');
list.a.next.next.next.next = new Node('s');
list.a.next.next.next.next.next = new Node('b');
list.b = new Node('g');
list.b.next = new Node('e');
list.b.next.next = new Node('e');
list.b.next.next.next = new Node('k');
list.b.next.next.next.next = new Node('s');
list.b.next.next.next.next.next = new Node('a');
int value;
value = list.compare(a, b);
System.out.println(value);
}
}
Output:
1
