Given pointer to the head node of a linked list, the task is to reverse the linked list.

Examples:

Input : Head of following linked list  
       1->2->3->4->NULL
Output : Linked list should be changed to,
       4->3->2->1->NULL

Input : Head of following linked list  
       1->2->3->4->5->NULL
Output : Linked list should be changed to,
       5->4->3->2->1->NULL

Input : NULL
Output : NULL

Input  : 1->NULL
Output : 1->NULL
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Iterative Method
Iterate trough the linked list. In loop, change next to prev, prev to current and current to next

Java Programming:

#include<stdio.h>
#include<stdlib.h>
 
/* Link list node */
struct node
{
    int data;
    struct node* next;
};
 
/* Function to reverse the linked list */
static void reverse(struct node** head_ref)
{
    struct node* prev   = NULL;
    struct node* current = *head_ref;
    struct node* next;
    while (current != NULL)
    {
        next  = current->next;  
        current->next = prev;   
        prev = current;
        current = next;
    }
    *head_ref = prev;
}
 
/* Function to push a node */
void push(struct node** head_ref, int new_data)
{
    /* allocate node */
    struct node* new_node =
            (struct node*) malloc(sizeof(struct node));
            
    /* put in the data  */
    new_node->data  = new_data;
                
    /* link the old list off the new node */
    new_node->next = (*head_ref);    
        
    /* move the head to point to the new node */
    (*head_ref)    = new_node;
}
 
/* Function to print linked list */
void printList(struct node *head)
{
    struct node *temp = head;
    while(temp != NULL)
    {
        printf("%d  ", temp->data);    
        temp = temp->next;  
    }
}    
 
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct node* head = NULL;
   
     push(&head, 20);
     push(&head, 4);
     push(&head, 15); 
     push(&head, 85);      
     
     printf("Given linked list\n");
     printList(head);    
     reverse(&head);                      
     printf("\nReversed Linked list \n");
     printList(head);    
     getchar();
}
Given linked list
85 15 4 20 
Reversed Linked list 
20 4 15 85

Time Complexity: O(n)
Space Complexity: O(1)

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Recursive Method:

   1) Divide the list in two parts - first node and rest of the linked list.
   2) Call reverse for the rest of the linked list.
   3) Link rest to first.
   4) Fix head pointer

Write a function to reverse a linked list

C Programming:

void recursiveReverse(struct node** head_ref)
{
    struct node* first;
    struct node* rest;
      
    /* empty list */
    if (*head_ref == NULL)
       return;   
 
    /* suppose first = {1, 2, 3}, rest = {2, 3} */
    first = *head_ref;  
    rest  = first->next;
 
    /* List has only one node */
    if (rest == NULL)
       return;   
 
    /* reverse the rest list and put the first element at the end */
    recursiveReverse(&rest);
    first->next->next  = first;  
     
    /* tricky step -- see the diagram */
    first->next  = NULL;          
 
    /* fix the head pointer */
    *head_ref = rest;              
}

Time Complexity: O(n)
Space Complexity: O(1)

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Java Programming:

// Java program for reversing the Linked list
 
class LinkedList {
 
    static Node head;
 
    static class Node {
 
        int data;
        Node next;
 
        Node(int d) {
            data = d;
            next = null;
        }
    }
 
    // A simple and tail recursive function to reverse
    // a linked list.  prev is passed as NULL initially.
    Node reverseUtil(Node curr, Node prev) {
 
        /* If last node mark it head*/
        if (curr.next == null) {
            head = curr;
 
            /* Update next to prev node */
            curr.next = prev;
            return null;
        }
 
        /* Save curr->next node for recursive call */
        Node next1 = curr.next;
 
        /* and update next ..*/
        curr.next = prev;
 
        reverseUtil(next1, curr);
        return head;
    }
 
    // prints content of double linked list
    void printList(Node node) {
        while (node != null) {
            System.out.print(node.data + " ");
            node = node.next;
        }
    }
 
    public static void main(String[] args) {
        LinkedList list = new LinkedList();
        list.head = new Node(1);
        list.head.next = new Node(2);
        list.head.next.next = new Node(3);
        list.head.next.next.next = new Node(4);
        list.head.next.next.next.next = new Node(5);
        list.head.next.next.next.next.next = new Node(6);
        list.head.next.next.next.next.next.next = new Node(7);
        list.head.next.next.next.next.next.next.next = new Node(8);
 
        System.out.println("Original Linked list ");
        list.printList(head);
        Node res = list.reverseUtil(head, null);
        System.out.println("");
        System.out.println("");
        System.out.println("Reversed linked list ");
        list.printList(res);
    }
}
 
 
// This code has been contributed by Mayank Jaiswal
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Output:

Given linked list
1 2 3 4 5 6 7 8

Reversed linked list
8 7 6 5 4 3 2 1

Categorized in:

CodingJAVALinked ListSingly Linked List

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