Given a string, reverse it using stack. For example “GeeksQuiz” should be converted to “ziuQskeeG”.
Following is simple algorithm to reverse a string using stack.
1) Create an empty stack.
2) One by one push all characters of string to stack.
3) One by one pop all characters from stack and put
them back to string.
Following are C and Python programs that implements above algorithm.
Java Programming:
/* Java program to reverse
String using Stack */
import java.util.*;
//stack
class Stack
{
int size;
int top;
char[] a;
//function to check if stack is empty
boolean isEmpty()
{
return (top < 0);
}
Stack(int n)
{
top = -1;
size = n;
a = new char[size];
}
//function to push element in Stack
boolean push(char x)
{
if (top >= size)
{
System.out.println("Stack Overflow");
return false;
}
else
{
a[++top] = x;
return true;
}
}
//function to pop element from stack
char pop()
{
if (top < 0)
{
System.out.println("Stack Underflow");
return 0;
}
else
{
char x = a[top--];
return x;
}
}
}
// Driver code
class Main
{
//function to reverse the string
public static void reverse(StringBuffer str)
{
// Create a stack of capacity
// equal to length of string
int n = str.length();
Stack obj = new Stack(n);
// Push all characters of string
// to stack
int i;
for (i = 0; i < n; i++)
obj.push(str.charAt(i));
// Pop all characters of string
// and put them back to str
for (i = 0; i < n; i++)
{
char ch = obj.pop();
str.setCharAt(i,ch);
}
}
//driver function
public static void main(String args[])
{
//create a new string
StringBuffer s= new StringBuffer("GeeksforGeeks");
//call reverse method
reverse(s);
//print the reversed string
System.out.println("Reversed string is : " + s);
}
}
Output:
Reversed string is ziuQskeeG
Time Complexity: O(n) where n is number of characters in stack.
Auxiliary Space: O(n) for stack.
A string can also be reversed without using any auxiliary space. Following C and Python programs to implement reverse without using stack.
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