Given a Directed Graph and two vertices in it, check whether there is a path from the first given vertex to second. For example, in the following graph, there is a path from vertex 1 to 3. As another example, there is no path from 3 to 0.
We can either use Breadth First Search (BFS) or Depth First Search (DFS) to find path between two vertices. Take the first vertex as source in BFS (or DFS), follow the standard BFS (or DFS). If we see the second vertex in our traversal, then return true. Else return false.
Following are C++,Java and Python codes that use BFS for finding reachability of second vertex from first vertex.
C++ Programming
#include<iostream>
#include <list>
using namespace std;
class Graph
{
int V;
list<int> *adj;
public:
Graph(int V);
void addEdge(int v, int w);
bool isReachable(int s, int d);
};
Graph::Graph(int V)
{
this->V = V;
adj = new list<int>[V];
}
void Graph::addEdge(int v, int w)
{
adj[v].push_back(w);
}
bool Graph::isReachable(int s, int d)
{
if (s == d)
return true;
bool *visited = new bool[V];
for (int i = 0; i < V; i++)
visited[i] = false;
list<int> queue;
visited[s] = true;
queue.push_back(s);
list<int>::iterator i;
while (!queue.empty())
{
s = queue.front();
queue.pop_front();
for (i = adj[s].begin(); i != adj[s].end(); ++i)
{
if (*i == d)
return true;
if (!visited[*i])
{
visited[*i] = true;
queue.push_back(*i);
}
}
}
return false;
}
int main()
{
Graph g(4);
g.addEdge(0, 1);
g.addEdge(0, 2);
g.addEdge(1, 2);
g.addEdge(2, 0);
g.addEdge(2, 3);
g.addEdge(3, 3);
int u = 1, v = 3;
if(g.isReachable(u, v))
cout<< "\n There is a path from " << u << " to " << v;
else
cout<< "\n There is no path from " << u << " to " << v;
u = 3, v = 1;
if(g.isReachable(u, v))
cout<< "\n There is a path from " << u << " to " << v;
else
cout<< "\n There is no path from " << u << " to " << v;
return 0;
}
Output:
There is a path from 1 to 3
There is no path from 3 to 1
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