Given a linked list, print reverse of it using a recursive function. For example, if the given linked list is 1->2->3->4, then output should be 4->3->2->1.
Note that the question is only about printing the reverse. To reverse the list itself see this
Difficulty Level: Rookie
Algorithm
printReverse(head)
1. call print reverse for hed->next
2. print head->data
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C Programming:
// C program to print reverse of a linked list
#include<stdio.h>
#include<stdlib.h>
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to reverse the linked list */
void printReverse(struct node* head)
{
// Base case
if (head == NULL)
return;
// print the list after head node
printReverse(head->next);
// After everything else is printed, print head
printf("%d ", head->data);
}
/*UTILITY FUNCTIONS*/
/* Push a node to linked list. Note that this function
changes the head */
void push(struct node** head_ref, char new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to pochar to the new node */
(*head_ref) = new_node;
}
/* Drier program to test above function*/
int main()
{
// Let us create linked list 1->2->3->4
struct node* head = NULL;
push(&head, 4);
push(&head, 3);
push(&head, 2);
push(&head, 1);
printReverse(head);
return 0;
}
Output:
4 3 2 1
Time Complexity: O(n)
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