Given a singly linked list and a position, delete a linked list node at the given position.
Example:
Input: position = 1, Linked List = 8->2->3->1->7
Output: Linked List = 8->3->1->7
Input: position = 0, Linked List = 8->2->3->1->7
Output: Linked List = 2->3->1->7
If node to be deleted is root, simply delete it. To delete a middle node, we must have pointer to the node previous to the node to be deleted. So if positions is not zero, we run a loop position-1 times and get pointer to the previous node.
C++ Programming:
#include <stdio.h>
#include <stdlib.h>
struct node
{
int data;
struct node *next;
};
void push(struct node** head_ref, int new_data)
{
struct node* new_node = (struct node*) malloc(sizeof(struct node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
void deleteNode(struct node **head_ref, int position)
{
if (*head_ref == NULL)
return;
struct node* temp = *head_ref;
if (position == 0)
{
*head_ref = temp->next;
free(temp);
return;
}
for (int i=0; temp!=NULL && i<position-1; i++)
temp = temp->next;
if (temp == NULL || temp->next == NULL)
return;
struct node *next = temp->next->next;
free(temp->next);
temp->next = next;
}
void printList(struct node *node)
{
while (node != NULL)
{
printf(" %d ", node->data);
node = node->next;
}
}
int main()
{
struct node* head = NULL;
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
push(&head, 8);
puts("Created Linked List: ");
printList(head);
deleteNode(&head, 4);
puts("\nLinked List after Deletion at position 4: ");
printList(head);
return 0;
}
Output:
Created Linked List:
8 2 3 1 7
Linked List after Deletion at position 4:
8 2 3 1
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