In the previous post, we introduced Queue and discussed array implementation. In this post, linked list implementation is discussed. The following two main operations must be implemented efficiently.

In a Queue data structure, we maintain two pointers, front and rear. The front points the first item of queue and rear points to last item.

enQueue() This operation adds a new node after rear and moves rear to the next node.

deQueue() This operation removes the front node and moves front to the next node.

Java programming

// Java program for linked-list implementation of queue

// A linked list (LL) node to store a queue entry
class QNode
{
int key;
QNode next;

// constructor to create a new linked list node
public QNode(int key) {
this.key = key;
this.next = null;
}
}

// A class to represent a queue
//The queue, front stores the front node of LL and rear stores ths
//last node of LL
class Queue
{
QNode front, rear;

public Queue() {
this.front = this.rear = null;
}

// Method to add an key to the queue.
void enqueue(int key)
{

// Create a new LL node
QNode temp = new QNode(key);

// If queue is empty, then new node is front and rear both
if (this.rear == null)
{
this.front = this.rear = temp;
return;
}

// Add the new node at the end of queue and change rear
this.rear.next = temp;
this.rear = temp;
}

// Method to remove an key from queue.
QNode dequeue()
{
// If queue is empty, return NULL.
if (this.front == null)
return null;

// Store previous front and move front one node ahead
QNode temp = this.front;
this.front = this.front.next;

// If front becomes NULL, then change rear also as NULL
if (this.front == null)
this.rear = null;
return temp;
}
}


// Driver class
public class Test
{
public static void main(String[] args)
{
Queue q=new Queue();
q.enqueue(10);
q.enqueue(20);
q.dequeue();
q.dequeue();
q.enqueue(30);
q.enqueue(40);
q.enqueue(50);

System.out.println("Dequeued item is "+ q.dequeue().key);
}
}

 Output:

Dequeued item is 30

Time Complexity: Time complexity of both operations enqueue() and dequeue() is O(1) as we only change few pointers in both operations. There is no loop in any of the operations.

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