Quick Sort on Doubly Linked List is discussed here. Quick Sort on Singly linked list was given as an exercise. Following is C++ implementation for same. The important things about implementation are, it changes pointers rather swapping data and time complexity is same as the implementation for Doubly Linked List.
In partition(), we consider last element as pivot. We traverse through the current list and if a node has value greater than pivot, we move it after tail. If the node has smaller value, we keep it at its current position.
In QuickSortRecur(), we first call partition() which places pivot at correct position and returns pivot. After pivot is placed at correct position, we find tail node of left side (list before pivot) and recur for left list. Finally, we recur for right list.

c++
// C++ program for Quick Sort on Singly Linled List
#include <iostream>
#include <cstdio>
using namespace std;

/* a node of the singly linked list */
struct node
{
int data;
struct node *next;
};

/* A utility function to insert a node at the beginning of linked list */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node = new node;

/* put in the data */
new_node->data = new_data;

/* link the old list off the new node */
new_node->next = (*head_ref);

/* move the head to point to the new node */
(*head_ref) = new_node;
}

/* A utility function to print linked list */
void printList(struct node *node)
{
while (node != NULL)
{
printf("%d ", node->data);
node = node->next;
}
printf("\n");
}

// Returns the last node of the list
struct node *getTail(struct node *cur)
{
while (cur != NULL && cur->next != NULL)
cur = cur->next;
return cur;
}

// Partitions the list taking the last element as the pivot
struct node *partition(struct node *head, struct node *end,
struct node **newHead, struct node **newEnd)
{
struct node *pivot = end;
struct node *prev = NULL, *cur = head, *tail = pivot;

// During partition, both the head and end of the list might change
// which is updated in the newHead and newEnd variables
while (cur != pivot)
{
if (cur->data < pivot->data)
{
// First node that has a value less than the pivot - becomes
// the new head
if ((*newHead) == NULL)
(*newHead) = cur;

prev = cur;
cur = cur->next;
}
else // If cur node is greater than pivot
{
// Move cur node to next of tail, and change tail
if (prev)
prev->next = cur->next;
struct node *tmp = cur->next;
cur->next = NULL;
tail->next = cur;
tail = cur;
cur = tmp;
}
}

// If the pivot data is the smallest element in the current list,
// pivot becomes the head
if ((*newHead) == NULL)
(*newHead) = pivot;

// Update newEnd to the current last node
(*newEnd) = tail;

// Return the pivot node
return pivot;
}


//here the sorting happens exclusive of the end node
struct node *quickSortRecur(struct node *head, struct node *end)
{
// base condition
if (!head || head == end)
return head;

node *newHead = NULL, *newEnd = NULL;

// Partition the list, newHead and newEnd will be updated
// by the partition function
struct node *pivot = partition(head, end, &newHead, &newEnd);

// If pivot is the smallest element - no need to recur for
// the left part.
if (newHead != pivot)
{
// Set the node before the pivot node as NULL
struct node *tmp = newHead;
while (tmp->next != pivot)
tmp = tmp->next;
tmp->next = NULL;

// Recur for the list before pivot
newHead = quickSortRecur(newHead, tmp);

// Change next of last node of the left half to pivot
tmp = getTail(newHead);
tmp->next = pivot;
}

// Recur for the list after the pivot element
pivot->next = quickSortRecur(pivot->next, newEnd);

return newHead;
}

// The main function for quick sort. This is a wrapper over recursive
// function quickSortRecur()
void quickSort(struct node **headRef)
{
(*headRef) = quickSortRecur(*headRef, getTail(*headRef));
return;
}

// Driver program to test above functions
int main()
{
struct node *a = NULL;
push(&a, 5);
push(&a, 20);
push(&a, 4);
push(&a, 3);
push(&a, 30);

cout << "Linked List before sorting \n";
printList(a);

quickSort(&a);

cout << "Linked List after sorting \n";
printList(a);

return 0;
}

Output:

Linked List before sorting
30  3  4  20  5
Linked List after sorting
3  4  5  20  30
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