What is Kruskals Minimum Spanning Tree Algorithm?

Given a connected and undirected graph, a spanning tree of that graph is a subgraph that is a tree and connects all the vertices together. A single graph can have many different spanning trees. A minimum spanning tree (MST) or minimum weight spanning tree for a weighted, connected and undirected graph is a spanning tree with weight less than or equal to the weight of every other spanning tree. The weight of a spanning tree is the sum of weights given to each edge of the spanning tree.

How many edges does a minimum spanning tree has?

A minimum spanning tree has (V – 1) edges where V is the number of vertices in the given graph.

What are the applications of Minimum Spanning Tree?

See this for applications of MST.

Below are the steps for finding MST using Kruskal’s algorithm

Sort all the edges in non-decreasing order of their weight.

Pick the smallest edge. Check if it forms a cycle with the spanning tree 
formed so far. If cycle is not formed, include this edge. Else, discard it.  

Repeat step#2 until there are (V-1) edges in the spanning tree.
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The step#2 uses Union-Find algorithm to detect cycle. So we recommend to read following post as a prerequisite.

Union-Find Algorithm | Set 1 (Detect Cycle in a Graph)

Union-Find Algorithm | Set 2 (Union By Rank and Path Compression)

The algorithm is a Greedy Algorithm. The Greedy Choice is to pick the smallest weight edge that does not cause a cycle in the MST constructed so far. Let us understand it with an example: Consider the below input graph.

Kruskal’s Minimum Spanning Tree Algorithm

The graph contains 9 vertices and 14 edges. So, the minimum spanning tree formed will be having (9 – 1) = 8 edges.

After sorting:
Weight   Src    Dest
1         7      6
2         8      2
2         6      5
4         0      1
4         2      5
6         8      6
7         2      3
7         7      8
8         0      7
8         1      2
9         3      4
10        5      4
11        1      7
14        3      5

Now pick all edges one by one from sorted list of edges

1. Pick edge 7-6: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

2. Pick edge 8-2: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

3. Pick edge 6-5: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

4. Pick edge 0-1: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

5. Pick edge 2-5: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

6. Pick edge 8-6: Since including this edge results in cycle, discard it.

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7. Pick edge 2-3: No cycle is formed, include it.

 

Kruskal’s Minimum Spanning Tree Algorithm

8. Pick edge 7-8: Since including this edge results in cycle, discard it.

9. Pick edge 0-7: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

10. Pick edge 1-2: Since including this edge results in cycle, discard it.

11. Pick edge 3-4: No cycle is formed, include it.

Kruskal’s Minimum Spanning Tree Algorithm

Since the number of edges included equals (V – 1), the algorithm stops here.

Recommended:

Please try your approach on {IDE} first, before moving on to the solution.

C++

// C++ program for Kruskal's algorithm to find Minimum Spanning Tree
// of a given connected, undirected and weighted graph
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// a structure to represent a weighted edge in graph
struct Edge
{
int src, dest, weight;
};

// a structure to represent a connected, undirected and weighted graph
struct Graph
{
// V-> Number of vertices, E-> Number of edges
int V, E;

// graph is represented as an array of edges. Since the graph is
// undirected, the edge from src to dest is also edge from dest
// to src. Both are counted as 1 edge here.
struct Edge* edge;
};

// Creates a graph with V vertices and E edges
struct Graph* createGraph(int V, int E)
{
struct Graph* graph = (struct Graph*) malloc( sizeof(struct Graph) );
graph->V = V;
graph->E = E;

graph->edge = (struct Edge*) malloc( graph->E * sizeof( struct Edge ) );

return graph;
}

// A structure to represent a subset for union-find
struct subset
{
int parent;
int rank;
};

// A utility function to find set of an element i
// (uses path compression technique)
int find(struct subset subsets[], int i)
{
// find root and make root as parent of i (path compression)
if (subsets[i].parent != i)
subsets[i].parent = find(subsets, subsets[i].parent);

return subsets[i].parent;
}

// A function that does union of two sets of x and y
// (uses union by rank)
void Union(struct subset subsets[], int x, int y)
{
int xroot = find(subsets, x);
int yroot = find(subsets, y);

// Attach smaller rank tree under root of high rank tree
// (Union by Rank)
if (subsets[xroot].rank < subsets[yroot].rank)
subsets[xroot].parent = yroot;
else if (subsets[xroot].rank > subsets[yroot].rank)
subsets[yroot].parent = xroot;

// If ranks are same, then make one as root and increment
// its rank by one
else
{
subsets[yroot].parent = xroot;
subsets[xroot].rank++;
}
}

// Compare two edges according to their weights.
// Used in qsort() for sorting an array of edges
int myComp(const void* a, const void* b)
{
struct Edge* a1 = (struct Edge*)a;
struct Edge* b1 = (struct Edge*)b;
return a1->weight > b1->weight;
}

// The main function to construct MST using Kruskal's algorithm
void KruskalMST(struct Graph* graph)
{
int V = graph->V;
struct Edge result[V]; // Tnis will store the resultant MST
int e = 0; // An index variable, used for result[]
int i = 0; // An index variable, used for sorted edges

// Step 1: Sort all the edges in non-decreasing order of their weight
// If we are not allowed to change the given graph, we can create a copy of
// array of edges
qsort(graph->edge, graph->E, sizeof(graph->edge[0]), myComp);

// Allocate memory for creating V ssubsets
struct subset *subsets =
(struct subset*) malloc( V * sizeof(struct subset) );

// Create V subsets with single elements
for (int v = 0; v < V; ++v)
{
subsets[v].parent = v;
subsets[v].rank = 0;
}

// Number of edges to be taken is equal to V-1
while (e < V - 1)
{
// Step 2: Pick the smallest edge. And increment the index
// for next iteration
struct Edge next_edge = graph->edge[i++];

int x = find(subsets, next_edge.src);
int y = find(subsets, next_edge.dest);

// If including this edge does't cause cycle, include it
// in result and increment the index of result for next edge
if (x != y)
{
result[e++] = next_edge;
Union(subsets, x, y);
}
// Else discard the next_edge
}

// print the contents of result[] to display the built MST
printf("Following are the edges in the constructed MST\n");
for (i = 0; i < e; ++i)
printf("%d -- %d == %d\n", result[i].src, result[i].dest,
result[i].weight);
return;
}

// Driver program to test above functions
int main()
{
/* Let us create following weighted graph
10
0--------1
| \ |
6| 5\ |15
| \ |
2--------3
4 */
int V = 4; // Number of vertices in graph
int E = 5; // Number of edges in graph
struct Graph* graph = createGraph(V, E);


// add edge 0-1
graph->edge[0].src = 0;
graph->edge[0].dest = 1;
graph->edge[0].weight = 10;

// add edge 0-2
graph->edge[1].src = 0;
graph->edge[1].dest = 2;
graph->edge[1].weight = 6;

// add edge 0-3
graph->edge[2].src = 0;
graph->edge[2].dest = 3;
graph->edge[2].weight = 5;

// add edge 1-3
graph->edge[3].src = 1;
graph->edge[3].dest = 3;
graph->edge[3].weight = 15;

// add edge 2-3
graph->edge[4].src = 2;
graph->edge[4].dest = 3;
graph->edge[4].weight = 4;

KruskalMST(graph);

return 0;
}

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JAVA

// Java program for Kruskal's algorithm to find Minimum Spanning Tree
// of a given connected, undirected and weighted graph
import java.util.*;
import java.lang.*;
import java.io.*;

class Graph
{
// A class to represent a graph edge
class Edge implements Comparable<Edge>
{
int src, dest, weight;

// Comparator function used for sorting edges based on
// their weight
public int compareTo(Edge compareEdge)
{
return this.weight-compareEdge.weight;
}
};

// A class to represent a subset for union-find
class subset
{
int parent, rank;
};

int V, E; // V-> no. of vertices & E->no.of edges
Edge edge[]; // collection of all edges

// Creates a graph with V vertices and E edges
Graph(int v, int e)
{
V = v;
E = e;
edge = new Edge[E];
for (int i=0; i<e; ++i)
edge[i] = new Edge();
}

// A utility function to find set of an element i
// (uses path compression technique)
int find(subset subsets[], int i)
{
// find root and make root as parent of i (path compression)
if (subsets[i].parent != i)
subsets[i].parent = find(subsets, subsets[i].parent);

return subsets[i].parent;
}

// A function that does union of two sets of x and y
// (uses union by rank)
void Union(subset subsets[], int x, int y)
{
int xroot = find(subsets, x);
int yroot = find(subsets, y);

// Attach smaller rank tree under root of high rank tree
// (Union by Rank)
if (subsets[xroot].rank < subsets[yroot].rank)
subsets[xroot].parent = yroot;
else if (subsets[xroot].rank > subsets[yroot].rank)
subsets[yroot].parent = xroot;

// If ranks are same, then make one as root and increment
// its rank by one
else
{
subsets[yroot].parent = xroot;
subsets[xroot].rank++;
}
}

// The main function to construct MST using Kruskal's algorithm
void KruskalMST()
{
Edge result[] = new Edge[V]; // Tnis will store the resultant MST
int e = 0; // An index variable, used for result[]
int i = 0; // An index variable, used for sorted edges
for (i=0; i<V; ++i)
result[i] = new Edge();

// Step 1: Sort all the edges in non-decreasing order of their
// weight. If we are not allowed to change the given graph, we
// can create a copy of array of edges
Arrays.sort(edge);

// Allocate memory for creating V ssubsets
subset subsets[] = new subset[V];
for(i=0; i<V; ++i)
subsets[i]=new subset();

// Create V subsets with single elements
for (int v = 0; v < V; ++v)
{
subsets[v].parent = v;
subsets[v].rank = 0;
}

i = 0; // Index used to pick next edge

// Number of edges to be taken is equal to V-1
while (e < V - 1)
{
// Step 2: Pick the smallest edge. And increment the index
// for next iteration
Edge next_edge = new Edge();
next_edge = edge[i++];

int x = find(subsets, next_edge.src);
int y = find(subsets, next_edge.dest);

// If including this edge does't cause cycle, include it
// in result and increment the index of result for next edge
if (x != y)
{
result[e++] = next_edge;
Union(subsets, x, y);
}
// Else discard the next_edge
}

// print the contents of result[] to display the built MST
System.out.println("Following are the edges in the constructed MST");
for (i = 0; i < e; ++i)
System.out.println(result[i].src+" -- "+result[i].dest+" == "+
result[i].weight);
}

// Driver Program
public static void main (String[] args)
{

/* Let us create following weighted graph
10
0--------1
| \ |
6| 5\ |15
| \ |
2--------3
4 */
int V = 4; // Number of vertices in graph
int E = 5; // Number of edges in graph
Graph graph = new Graph(V, E);

// add edge 0-1
graph.edge[0].src = 0;
graph.edge[0].dest = 1;
graph.edge[0].weight = 10;

// add edge 0-2
graph.edge[1].src = 0;
graph.edge[1].dest = 2;
graph.edge[1].weight = 6;

// add edge 0-3
graph.edge[2].src = 0;
graph.edge[2].dest = 3;
graph.edge[2].weight = 5;

// add edge 1-3
graph.edge[3].src = 1;
graph.edge[3].dest = 3;
graph.edge[3].weight = 15;

// add edge 2-3
graph.edge[4].src = 2;
graph.edge[4].dest = 3;
graph.edge[4].weight = 4;

graph.KruskalMST();
}
}
//This code is contributed by Aakash Hasija

Python

Python
# Python program for Kruskal's algorithm to find Minimum Spanning Tree
# of a given connected, undirected and weighted graph

from collections import defaultdict

#Class to represent a graph
class Graph:

def __init__(self,vertices):
self.V= vertices #No. of vertices
self.graph = [] # default dictionary to store graph


# function to add an edge to graph
def addEdge(self,u,v,w):
self.graph.append([u,v,w])

# A utility function to find set of an element i
# (uses path compression technique)
def find(self, parent, i):
if parent[i] == i:
return i
return self.find(parent, parent[i])

# A function that does union of two sets of x and y
# (uses union by rank)
def union(self, parent, rank, x, y):
xroot = self.find(parent, x)
yroot = self.find(parent, y)

# Attach smaller rank tree under root of high rank tree
# (Union by Rank)
if rank[xroot] < rank[yroot]:
parent[xroot] = yroot
elif rank[xroot] > rank[yroot]:
parent[yroot] = xroot
#If ranks are same, then make one as root and increment
# its rank by one
else :
parent[yroot] = xroot
rank[xroot] += 1

# The main function to construct MST using Kruskal's algorithm
def KruskalMST(self):

result =[] #This will store the resultant MST

i = 0 # An index variable, used for sorted edges
e = 0 # An index variable, used for result[]

#Step 1: Sort all the edges in non-decreasing order of their
# weight. If we are not allowed to change the given graph, we
# can create a copy of graph
self.graph = sorted(self.graph,key=lambda item: item[2])
#print self.graph

parent = [] ; rank = []

# Create V subsets with single elements
for node in range(self.V):
parent.append(node)
rank.append(0)

# Number of edges to be taken is equal to V-1
while e < self.V -1 :

# Step 2: Pick the smallest edge and increment the index
# for next iteration
u,v,w = self.graph[i]
i = i + 1
x = self.find(parent, u)
y = self.find(parent ,v)

# If including this edge does't cause cycle, include it
# in result and increment the index of result for next edge
if x != y:
e = e + 1
result.append([u,v,w])
self.union(parent, rank, x, y)
# Else discard the edge

# print the contents of result[] to display the built MST
print "Following are the edges in the constructed MST"
for u,v,weight in result:
#print str(u) + " -- " + str(v) + " == " + str(weight)
print ("%d -- %d == %d" % (u,v,weight))


g = Graph(4)
g.addEdge(0, 1, 10)
g.addEdge(0, 2, 6)
g.addEdge(0, 3, 5)
g.addEdge(1, 3, 15)
g.addEdge(2, 3, 4)

g.KruskalMST()

#This code is contributed by Neelam Yadav
Following are the edges in the constructed MST
2 -- 3 == 4
0 -- 3 == 5
0 -- 1 == 10

Time Complexity: O(ElogE) or O(ElogV). Sorting of edges takes O(ELogE) time. After sorting, we iterate through all edges and apply find-union algorithm. The find and union operations can take atmost O(LogV) time. So overall complexity is O(ELogE + ELogV) time. The value of E can be atmost O(V2), so O(LogV) are O(LogE) same. Therefore, overall time complexity is O(ElogE) or O(ElogV)

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