1 red ball can be selected in ⁴C₁ ways 1 white ball can be selected in ³C₁ ways 1 blue ball can be selected in ²C₁ ways
Total number of ways = ⁴C₁ x ³C₁ x ²C₁ = 4 x 3 x 2 = 24.

• Please note that we have multiplied the combination results, we use to add when their is OR condition, and we use to multiply when there is AND condition.
• In this question it is AND as 1 red AND 1 White AND 1 Blue, so we multiplied