Find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively ?

A. 20

B. 12

C. 6

D. 48

Answer : B. 12…

Explanation:

Remainder in case of 148 = 4
Number = 148 – 4 = 144
Remainder in case of 246 = 6
Number = 246 – 6 = 240
Remainder in case of 623 = 11
Number = 623 – 11 = 612
Now, we have find the H.C.F. of 144, 240 and 612

H.C.F. of 144, 240 and 612 = 2 * 2 * 3 = 12

Therefore, the required number is 12 that will divide 148, 246 and 623 leaving remainders 4, 6 and 11 respectively.

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