What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?



What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?

A. 56

B. 128

C. 62

D. 32

Answer : C. 62


Explanation:


    Take the lcm of 3 , 4 , 5 , 6.
    3 = 3×1
    4 = 2×2
    5 = 5×1
    6 = 2×3
    LCM = 2 × 2 × 3 × 5 = 60
    Therefore 60 is the number that is completely divisible by these numbers. But we have to find the smallest number that leaves remainder 2.
    Answer : 60 + 2 = 62



What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6 ?